Limiting reactant calculations

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Often in many chemical processes a reactant is present in excess. The reactant that is present in excess is the chemical that remains after the reaction is completed. The reactant that is fully consumed during the reaction is called the limiting reagent. In combustion reactions, oxygen gas is usually present in excess in order for the the reaction to under complete combustion. Complete combustion means that the products of the reaction are CO2 (g) and H2O (l). Contrast to complete combustion is incomplete combustion. Incomplete combustion tends to form CO (g) as well as CO2 (g).

Example

(a) How many grams of carbon dioxide gas is produced when 20.5 grams of ethyl alcohol, C2H5OH, burns with 100.0 grams of oxygen, O2?

(b) Identify the limiting reagent and how much of the other reactant is left over?

Step 1: Identify the chemical equation involved: a combustion reaction.

Step 2: Write the balanced chemical equation.

Step 2a: Convert the mass of C2H5OH to moles of C2H5OH.
Step2a.gif
Step 2b: Convert the mass of O2 to moles of O2.
Step2b.gif

Step 3: Determine the stoichiometric ratio of the substances that you are working with, specifically:

  • between C2H5OH and O2
  • between C2H5OH and CO2
  • between O2 and CO2

Step 4: Using the moles of C2H5OH and O2 calculated in Step 2a and 2b, compare the mole ratio of C2H5OH : O2 to that obtained in Step 3. Determine which is present as the limiting reagent and which is present in excess.

Limiting mass mole step4 1.gif
C2H5OH is the limiting reactant.

Step 5: Calculate the amount of reactant that is left over.

Limiting mass mole step5.gif

External link

Limiting reagent


Content suitability

BCIT courses: CHEM 0011