Take out a piece
of paper and a pencil and go through this example with me. We will use algebra to solve for the coefficients. It's a 6-step process.
When propyl alcohol, CH3CH2CH2OH,
burns in air, it reacts with oxygen, O2, to form carbon dioxide,
CO2, and water, H2O. Write the balanced chemical
reaction.
Assign variables as coefficients for each substance
in the chemical equation.
Step 4
Determine the number of each type of atoms on
each side of the arrow.
Step 5
Write out the algebraic equations and solve
for the coefficients.
Step 6
Make sure that all the coefficients are whole
numbers. Multiply all the coefficients by an appropriate factor to convert
any fractions to whole numbers.
The balanced chemical equation is:
2 CH3CH2CH2OH (l) + 9O2 (g) 6CO2 (g) + 8H2O
(l)
Section
9.3 Guidelines
for Balancing Chemical Equations ..p219 Section
9.4 Examples Involving Balancing Equations ..p221