Take out a piece of paper and a pencil and go through this
example with me. We will balance this chemical equation by
inspection. It's a 6-step process.
When propyl alcohol, CH3CH2CH2OH,
burns in air, it reacts with oxygen, O2, to form carbon dioxide,
CO2, and water, H2O. Write the balanced chemical
reaction.
Count the number of
each type of atoms on both sides of the arrow.
Step 4
Decide the order of atom(s) to be
balanced.
start with the compound
that is made up of the most different kinds of elements.
pick the element(s) within
the compound that appear only in one substance on each
side of the arrow and balance it (them).
pick the element(s) within
the compound that appear more than once on each side of
the arrow and balance it (them).
Balance uncombined elements
last.
summary
Step 5
Balance each type of
atoms.
Step 6
Make sure that all the
coefficients are whole numbers. Multiply all the coefficients by an appropriate
factor to convert any fractions to whole numbers.
The balanced chemical equation is:
2 CH3CH2CH2OH (l) + 9O2 (g) 6CO2 (g) + 8H2O
(l)
Section
9.3 Guidelines
for Balancing Chemical Equations ..p219 Section
9.4 Examples Involving Balancing
Equations ..p221